In the Tukey test, if $\overline { \mathrm { X } } _ { 2 } = 6$ for a group of size $\mathrm { n } _ { 2 } = 7 , \quad \overline { \mathrm { X } } _ { 4 } = 14$ for a group of size $\mathrm { n } _ { 4 } = 7$, and the within-group variance $s _ { w } ^ { 2 } = 28$, then the $q$ test value for comparing group 2 to group 4 is:
A) -0.01
B) -0.29
C) -1.51
D) -4.00

Question

Quizplus · Accepted Answer

The Tukey test value $q$ is calculated using the formula $q = \frac{\overline{X}_2 - \overline{X}_4}{\sqrt{\frac{s_w^2}{n_2} + \frac{s_w^2}{n_4}}}$. Substituting the given values, $q = \frac{6 - 14}{\sqrt{\frac{28}{7} + \frac{28}{7}}} = \frac{-8}{\sqrt{8}} = -4.00$.

In the Tukey Test, If X‾2=6\overline { \mathrm { X } } _ { 2 } = 6X2​=6

In the Tukey Test, If $\overline { \mathrm { X } } _ { 2 } = 6$