If $r = - 0.879$ and $n = 6$, test the significance of the correlation coefficient at $\neq = .05$ A) Accept $- = 0$ because $4.20 2.78$ C) Accept $- = 0$ because $- 3.69 2.54$

Question

If $r = - 0.879$ and $n = 6$, test the significance of the correlation coefficient at $\neq = .05$ A) Accept $- = 0$ because $4.20 < 2.78$ B) Reject $= 0$ because $- 3.69 > 2.78$ C) Accept $- = 0$ because $- 3.69 < 2.54$ D) Reject $- = 0$ because $4.20 > 2.54$

Quizplus · Accepted Answer

The test statistic $ t $ is calculated as $ t = \frac{r\sqrt{n-2}}{\sqrt{1-r^2}} $. For $ r = -0.879 $ and $ n = 6 $, $ t \approx -3.69 $. The critical value for a two-tailed test with $ n-2 = 4 $ degrees of freedom at $\alpha = 0.05$ is approximately 2.78. Since $-3.69$ is less than $-2.78$, we reject the null hypothesis $ \rho = 0 $.

If r=−0.879r = - 0.879r=−0.879 And n=6n = 6n=6 , Test the Significance of the Correlation Coefficient At

If $r = - 0.879$ And $n = 6$ , Test the Significance of the Correlation Coefficient At