Find the domain of the function.
$$g ( p ) = \sqrt { 4 - p ^ { 2 } }$$
A) $- 2 \leq p \leq 2$
B) $p \leq - 2$ or $p \geq 2$
C) $p \geq 0$
D) $p \leq 2$
E) all real numbers

Question

Quizplus · Accepted Answer

The domain of $g(p) = \sqrt{4 - p^2}$ consists of all values of $p$ for which the expression under the square root, $4 - p^2$, is greater than or equal to 0. Solving the inequality $4 - p^2 \geq 0$ gives $p^2 \leq 4$, which implies $-2 \leq p \leq 2$.

Find the Domain of the Function g(p)=4−p2g ( p ) = \sqrt { 4 - p ^ { 2 } }g(p)=4−p2​

Find the Domain of the Function $g ( p ) = \sqrt { 4 - p ^ { 2 } }$