Solve the system of linear equations $\left\{ \begin{array} { l l } - 8 x + 24 y + 8 z & = 5 \ 16 x + 40 y & = 10 \ 24 x + 8 y - 16 z & = - 5 \end{array} \right.$ using an inverse matrix.
A) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 8 } \ 0 \ \frac { 15 } { 8 } \end{array} \right]$

B) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } 0 \ \frac { 5 } { 4 } \ - \frac { 5 } { 8 } \end{array} \right]$

C) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 8 } \ - \frac { 15 } { 8 } \ \frac { 5 } { 4 } \end{array} \right]$

D) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 8 } \ 0 \ \frac { 5 } { 4 } \end{array} \right]$

E) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 8 } \ - \frac { 15 } { 8 } \ - \frac { 5 } { 4 } \end{array} \right]$

Question

Solve the system of linear equations $\left\{ \begin{array} { l l } - 8 x + 24 y + 8 z & = 5 \ 16 x + 40 y & = 10 \ 24 x + 8 y - 16 z & = - 5 \end{array} \right.$ using an inverse matrix.
A) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 8 } \ 0 \ \frac { 15 } { 8 } \end{array} \right]$

B) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } 0 \ \frac { 5 } { 4 } \ - \frac { 5 } { 8 } \end{array} \right]$

C) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 8 } \ - \frac { 15 } { 8 } \ \frac { 5 } { 4 } \end{array} \right]$

D) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 8 } \ 0 \ \frac { 5 } { 4 } \end{array} \right]$

E) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 8 } \ - \frac { 15 } { 8 } \ - \frac { 5 } { 4 } \end{array} \right]$

Quizplus · Accepted Answer

The Answer of Solve the system of linear equations $\left\{ \begin{array} { l l } - 8 x + 24 y + 8 z & = 5 \ 16 x + 40 y & = 10 \ 24 x + 8 y - 16 z & = - 5 \end{array} \right.$ using an inverse matrix.
A) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 8 } \ 0 \ \frac { 15 } { 8 } \end{array} \right]$

B) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } 0 \ \frac { 5 } { 4 } \ - \frac { 5 } { 8 } \end{array} \right]$

C) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 8 } \ - \frac { 15 } { 8 } \ \frac { 5 } { 4 } \end{array} \right]$

D) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } \frac { 5 } { 8 } \ 0 \ \frac { 5 } { 4 } \end{array} \right]$

E) $\left[ \begin{array} { l } x \ y \ z \end{array} \right] = \left[ \begin{array} { c } - \frac { 5 } { 8 } \ - \frac { 15 } { 8 } \ - \frac { 5 } { 4 } \end{array} \right]$

Solve the System of Linear Equations {−8x+24y+8z=516x+40y=1024x+8y−16z=−5\left\{ \begin{array} { l l } - 8 x + 24 y + 8 z & = 5 \\ 16 x + 40 y & = 10 \\ 24 x + 8 y - 16 z & = - 5 \end{array} \right.⎩⎨⎧​−8x+24y+8z16x+40y24x+8y−16z​=5=10=−5​

Solve the System of Linear Equations $\left\{ \begin{array} { l l } - 8 x + 24 y + 8 z & = 5 \\ 16 x + 40 y & = 10 \\ 24 x + 8 y - 16 z & = - 5 \end{array} \right.$