Find the magnitude of the vector described below.
Initial point: $( 0 , - 6 , - 4 )$
Terminal point: $( - 1,5,5 )$
A) 19
B) 50
C) $\sqrt { 21 }$
D) $2 \sqrt { 203 }$
E) $\sqrt { 203 }$

Question

Quizplus · Accepted Answer

The magnitude of a vector from point $A(x_1, y_1, z_1)$ to point $B(x_2, y_2, z_2)$ is given by $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2}$. Substituting the given points, we get $\sqrt{(-1 - 0)^2 + (5 - (-6))^2 + (5 - (-4))^2} = \sqrt{1 + 121 + 81} = \sqrt{203}$.

Find the Magnitude of the Vector Described Below (0,−6,−4)( 0 , - 6 , - 4 )(0,−6,−4)

Find the Magnitude of the Vector Described Below $( 0 , - 6 , - 4 )$