The gravitational force between two masses is modeled using the following function: $F _ { g } ( r ) = G \frac { m _ { 1 } m _ { 2 } } { r ^ { 2 } }$
where $F _ { g } =$ gravitational force (Newtons)
$\begin{array} { l }
G = 6.673 \times 10 ^ { - 11 } \frac { \mathrm { N } \cdot \mathrm { m } ^ { 2 } } { \mathrm {~kg} ^ { 2 } } \
m _ { 1 } = \text { mass number } 1 \text { (kilograms) }
\end{array}$ $m _ { 2 } = \text { mass number } 2 \text { (kilograms) }$
$r =$ distance between centers of masses (meters) Which type of mathematical model is used here to describe the gravitational force?
A) Linear model
B) Nonlinear model
C) Exponential model
D) Trigonometric model

Question

The gravitational force between two masses is modeled using the following function: $F _ { g } ( r ) = G \frac { m _ { 1 } m _ { 2 } } { r ^ { 2 } }$
where $F _ { g } =$ gravitational force (Newtons)
$\begin{array} { l } 
G = 6.673 \times 10 ^ { - 11 } \frac { \mathrm { N } \cdot \mathrm { m } ^ { 2 } } { \mathrm {~kg} ^ { 2 } } \
m _ { 1 } = \text { mass number } 1 \text { (kilograms) }
\end{array}$ $m _ { 2 } = \text { mass number } 2 \text { (kilograms) }$
$r =$ distance between centers of masses (meters) Which type of mathematical model is used here to describe the gravitational force?
A) Linear model
B) Nonlinear model
C) Exponential model
D) Trigonometric model

Quizplus · Accepted Answer

The gravitational force model is nonlinear because the force is inversely proportional to the square of the distance between the two masses ($r^2$), which does not represent a linear relationship.

The Gravitational Force Between Two Masses Is Modeled Using the Following