A roll of aluminum foil from the grocery store is 12 inches wide by 75 feet long (if you unroll it). If the foil is 0.006 inches thick, and the specific weight of aluminum is $26460 \mathrm {~N} / \mathrm { m } ^ { 3 }$ ,
How much does the roll of aluminum foil weigh?
A) 142884N
B) 4900N
C) 0.036N
D) 28N

Question

Quizplus · Accepted Answer

The weight of the aluminum foil can be calculated by first finding its volume and then multiplying by the specific weight. The volume of the foil is its width times its length times its thickness. Convert dimensions to meters: width = 12 inches * 0.0254 m/inch = 0.3048 m, length = 75 feet * 0.3048 m/foot = 22.86 m, thickness = 0.006 inches * 0.0254 m/inch = 0.0001524 m. Volume = 0.3048 m * 22.86 m * 0.0001524 m = 1.06171264 cubic meters. Weight = Volume * Specific Weight = 1.06171264 m^3 * 26460 N/m^3 = 28.1 N, which rounds to 28 N.

A Roll of Aluminum Foil from the Grocery Store Is 26460 N/m326460 \mathrm {~N} / \mathrm { m } ^ { 3 }26460 N/m3

A Roll of Aluminum Foil from the Grocery Store Is $26460 \mathrm {~N} / \mathrm { m } ^ { 3 }$