Use the position equation $s = - 15 t ^ { 2 } + v _ { 0 } t + s _ { 0 }$ , where $S$ represents the height of an object (in feet), $v _ { 0 }$ represents the initial velocity of the object (in feet per second), $s _ { 0 }$ represents the Initial height of the object (in feet), and $t$ represents the time (in seconds).
A projectile is fired straight upward from ground level $\left( s _ { 0 } = 0 \right)$ with an initial velocity of $165$ feet Per second. At what instant will it be back at ground level?

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The Answer of Use the position equation $s = - 15 t ^ { 2 } + v _ { 0 } t + s _ { 0 }$ , where $S$ represents the height of an object (in feet), $v _ { 0 }$ represents the initial velocity of the object (in feet per second), $s _ { 0 }$ represents the Initial height of the object (in feet), and $t$ represents the time (in seconds).
A projectile is fired straight upward from ground level $\left( s _ { 0 } = 0 \right)$ with an initial velocity of $165$ feet Per second. At what instant will it be back at ground level?

Use the Position Equation s=−15t2+v0t+s0s = - 15 t ^ { 2 } + v _ { 0 } t + s _ { 0 }s=−15t2+v0​t+s0​

Use the Position Equation $s = - 15 t ^ { 2 } + v _ { 0 } t + s _ { 0 }$