A point in rectangular coordinates is given. Convert the point to polar coordinates. $( 7,7 )$
A)
Polar coordinates: $\left( - 7 \sqrt { 2 } , \frac { \pi } { 4 } \right)$
B)
Polar coordinates: $\left( \sqrt { 7 } , \frac { \pi } { 4 } \right)$
C)
Polar coordinates: $\left( 7 \sqrt { 2 } , \frac { \pi } { 4 } \right)$
D)
Polar coordinates: $\left( - \sqrt { 7 } , \frac { \pi } { 4 } \right)$
E)
Polar coordinates: $\left( 7 \sqrt { 2 } , - \frac { \pi } { 4 } \right)$

Question

A point in rectangular coordinates is given. Convert the point to polar coordinates. $( 7,7 )$ 
A)
Polar coordinates: $\left( - 7 \sqrt { 2 } , \frac { \pi } { 4 } \right)$
B)
Polar coordinates: $\left( \sqrt { 7 } , \frac { \pi } { 4 } \right)$
C)
Polar coordinates: $\left( 7 \sqrt { 2 } , \frac { \pi } { 4 } \right)$
D)
Polar coordinates: $\left( - \sqrt { 7 } , \frac { \pi } { 4 } \right)$
E)
Polar coordinates: $\left( 7 \sqrt { 2 } , - \frac { \pi } { 4 } \right)$

Quizplus · Accepted Answer

The polar coordinates $r$ and $\theta$ of a point $(x, y)$ can be found using $r = \sqrt{x^2 + y^2}$ and $\theta = \tan^{-1}\left(\frac{y}{x}\right)$. For the point $(7,7)$, $r = \sqrt{7^2 + 7^2} = 7\sqrt{2}$ and $\theta = \tan^{-1}\left(\frac{7}{7}\right) = \frac{\pi}{4}$, making the correct polar coordinates $\left(7\sqrt{2}, \frac{\pi}{4}\right)$.

A Point in Rectangular Coordinates Is Given (7,7)( 7,7 )(7,7) A) Polar Coordinates

A Point in Rectangular Coordinates Is Given $( 7,7 )$ A)
Polar Coordinates