$$\text { For paired samples, } \bar { x } _ { d } \text { and } \bar { x } _ { 1 } - \bar { x } _ { 2 } \text { are always numerically equal. }$$

Name: \[\text { For paired samples, } \bar { x } _ { d } \text { and } \bar { x } _ { 1 } - \bar { x } _ { 2 } \text { are always numerically equal. }\]
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Question

Quizplus · Accepted Answer

This is because $\bar{x}_d$ is defined as the mean of the differences between paired values, which is mathematically equivalent to $\bar{x}_1 - \bar{x}_2$. Therefore, they will always be numerically equal.

For paired samples, xˉd and xˉ1−xˉ2 are always numerically equal. \text { For paired samples, } \bar { x } _ { d } \text { and } \bar { x } _ { 1 } - \bar { x } _ { 2 } \text { are always numerically equal. } For paired samples, xˉd​ and xˉ1​−xˉ2​ are always numerically equal.

$\text { For paired samples, } \bar { x } _ { d } \text { and } \bar { x } _ { 1 } - \bar { x } _ { 2 } \text { are always numerically equal. }$