If electricity produced by the Three Gorges hydroelectric station is sold at a rate of $\$ 0.06$ per $\mathrm { kWh }$, what is the total revenue for 2008 based on actual power generated?

Question

Quizplus · Accepted Answer

The Answer is The number of kWh for each month is found from the graph in Energy Extra 11.2 by multiplying the output in MW times 1000 times the number of hours in the month. This is shown in the table below

\begin{array} { l l l l } \hline ext { month } & ext { MW } & ext { hours } & \mathrm { kWh } imes 10 ^ { 9 } \\hline ext { Jan } & 4000 & 744 & 2.976 \ ext { Feb } & 4000 & 696 & 2.784 \ ext { Mar } & 4000 & 744 & 2.976 \ ext { Apr } & 4300 & 720 & 3.096 \ ext { May } & 8600 & 744 & 6.398 \ ext { Jun } & 10000 & 720 & 7.200 \ ext { Jul } & 13500 & 744 & 10.044 \ ext { Aug } & 13500 & 744 & 10.044 \ ext { Sep } & 14200 & 720 & 10.224 \ ext { Oct } & 8400 & 744 & 6.250 \ ext { Nov } & 6000 & 720 & 4.320 \ ext { Dec } & 4500 & 744 & 3.348 \& & & \ ext { year total } & & & 69.660 \\hline\end{array}

The cost of the electricity produced is

\left( 6.966 imes 10 ^ { 10 } \mathrm { kWh } ight) imes \left( \$ 0.06 \mathrm { kWh } ^ { - 1 } ight) = \$ 4.18 imes 10 ^ { 9 }

If Electricity Produced by the Three Gorges Hydroelectric Station Is $0.06\$ 0.06$0.06

If Electricity Produced by the Three Gorges Hydroelectric Station Is $\$ 0.06$