The physical radius of a nucleus in units of fm is often approximated by the relation $r = 1.2 \times A ^ { 1 / 3 }$, where $A$ is the total number of nucleons. Compare the actual sizes of the deuteron and triton with the fusion cross sections for d-d and d-t fusion at an energy of $100 \mathrm { keV }$.

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The Answer of The physical radius of a nucleus in units of fm is often approximated by the relation $r = 1.2 \times A ^ { 1 / 3 }$, where $A$ is the total number of nucleons. Compare the actual sizes of the deuteron and triton with the fusion cross sections for d-d and d-t fusion at an energy of $100 \mathrm { keV }$.

The Physical Radius of a Nucleus in Units of Fm r=1.2×A1/3r = 1.2 \times A ^ { 1 / 3 }r=1.2×A1/3

The Physical Radius of a Nucleus in Units of Fm $r = 1.2 \times A ^ { 1 / 3 }$