Solve.
-$1.2 x - 3 \geq 0.7 x + 15.5$
A) $[ 37 , \infty )$
B) $( - \infty , 37 )$
C) $( 3.7 , \infty )$
D) $( - \infty , 37 ]$

Question

Quizplus · Accepted Answer

To solve the inequality $1.2x - 3 \geq 0.7x + 15.5$, first subtract $0.7x$ from both sides to get $0.5x - 3 \geq 15.5$. Then add 3 to both sides to get $0.5x \geq 18.5$. Finally, divide both sides by 0.5 to find $x \geq 37$, which corresponds to the interval $[37, \infty)$.

Solve - 1.2x−3≥0.7x+15.51.2 x - 3 \geq 0.7 x + 15.51.2x−3≥0.7x+15.5

Solve
- $1.2 x - 3 \geq 0.7 x + 15.5$