Solve.
-$$\frac { 1 } { 6 } ( 12 x + 66 ) - 19 - \frac { 1 } { 4 } ( 8 x - 32 )$$

Name: Solve. -\[\frac { 1 } { 6 } ( 12 x + 66 ) - 19 > - \frac { 1 } { 4 } ( 8 x - 32 )\]
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Question

Solve.
-$$\frac { 1 } { 6 } ( 12 x + 66 ) - 19 > - \frac { 1 } { 4 } ( 8 x - 32 )$$

Quizplus · Accepted Answer

First, simplify both sides of the inequality: $$\frac{1}{6}(12x + 66) - 19 > -\frac{1}{4}(8x - 32)$$$$2x + 11 - 19 > -2x + 8$$$$2x - 8 > -2x + 8$$Adding $2x$ to both sides and adding $8$ to both sides gives:$$4x > 16$$$$x > 4$$Therefore, the solution is $x > 4$, which corresponds to the interval $[4, \infty)$.

Solve - 16(12x+66)−19>−14(8x−32)\frac { 1 } { 6 } ( 12 x + 66 ) - 19 > - \frac { 1 } { 4 } ( 8 x - 32 )61​(12x+66)−19>−41​(8x−32)

Solve
- $\frac { 1 } { 6 } ( 12 x + 66 ) - 19 > - \frac { 1 } { 4 } ( 8 x - 32 )$