Solve the problem.
-The perimeter of a rectangle is $56 \mathrm {~cm}$. One side is $12 \mathrm {~cm}$ longer than the other side. Find the lengths of the sides.
A) $8 \mathrm {~cm} , 20 \mathrm {~cm}$
B) $11 \mathrm {~cm} , 23 \mathrm {~cm}$
C) $8 \mathrm {~cm} , 12 \mathrm {~cm}$
D) $16 \mathrm {~cm} , 28 \mathrm {~cm}$

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by $2l + 2w = 56$, where $l$ is the length and $w$ is the width. Given one side is $12 \mathrm{cm}$ longer than the other, we can set $l = w + 12$. Substituting and solving the equations, we find $w = 8 \mathrm{cm}$ and $l = 20 \mathrm{cm}$.

Solve the Problem 56 cm56 \mathrm {~cm}56 cm One Side Is 12 cm12 \mathrm {~cm}12 cm

Solve the Problem $56 \mathrm {~cm}$ One Side Is $12 \mathrm {~cm}$