Factor.
-$$y ^ { 2 } + 0.6 y - 0.16$$
A) $( y - 0.8 ) ( y - 0.2 )$
B) $( \mathrm { y } + 0.8 ) ( \mathrm { y } - 0.2 )$
C) $( y + 0.3 ) ^ { 2 }$
D) $( \mathrm { y } - 0.8 ) ( \mathrm { y } + 0.2 )$

Question

Quizplus · Accepted Answer

The correct factorization of $y^2 + 0.6y - 0.16$ is $(y + 0.8)(y - 0.2)$, because when multiplied, it gives the original quadratic equation.

Factor - y2+0.6y−0.16y ^ { 2 } + 0.6 y - 0.16y2+0.6y−0.16

Factor
- $y ^ { 2 } + 0.6 y - 0.16$