Factor using the ac-method.
-$$8 x ^ { 2 } - 10 x t - 3 t ^ { 2 }$$
A) prime
B) $( 8 x + t ) ( x - 3 t )$
C) $( 4 x - t ) ( 2 x + 3 t )$
D) $( 4 x + t ) ( 2 x - 3 t )$

Question

Quizplus · Accepted Answer

Using the ac-method, the product of 8 and -3 is -24. The factors of -24 that add up to -10 are 4 and -6. Then, we can rewrite the middle term as -6x + 4x. Thus,
$$8x^2 - 10xt - 3t^2 = 8x^2 - 6xt + 4xt - 3t^2 = 2x(4x - t) + (4x - t)(-3t) = (4x-t)(2x-3t)$$
So, the answer is D.

Factor Using the Ac-Method 8x2−10xt−3t28 x ^ { 2 } - 10 x t - 3 t ^ { 2 }8x2−10xt−3t2

Factor Using the Ac-Method $8 x ^ { 2 } - 10 x t - 3 t ^ { 2 }$