Factor completely.
-$$\mathrm { x } ^ { 2 } + 40 \mathrm { x } + 400$$
A) $( x + 20 ) ( x - 20 )$
B) $( x - 20 ) ^ { 2 }$
C) Prime
D) $( x + 20 ) ^ { 2 }$

Name: Factor completely. -\[\mathrm { x } ^ { 2 } + 40 \mathrm { x } + 400\] A) $( x + 20 ) ( x - 20 )$ B) $( x - 20 ) ^ { 2 }$ C) Prime D) $( x + 20 ) ^ { 2 }$
Brand: Quizplus
Rating: 4.9 (45 reviews)

Question

Quizplus · Accepted Answer

This is a perfect square trinomial, factoring to $(x + 20)^2$, because $20^2 = 400$ and $2 \cdot 20 \cdot x = 40x$.

Factor Completely x2+40x+400\mathrm { x } ^ { 2 } + 40 \mathrm { x } + 400x2+40x+400

Factor Completely $\mathrm { x } ^ { 2 } + 40 \mathrm { x } + 400$