Factor completely.
-$$y ^ { 2 } - 36$$
A) $\left( y ^ { 2 } + 6 \right) \left( y ^ { 2 } - 6 \right)$
B) $( y + 6 ) ( y - 6 )$
C) $( y - 6 ) ( y - 6 )$
D) $( y + 36 ) ( y - 36 )$

Question

Quizplus · Accepted Answer

The given expression is a difference of squares expression, which can be factored as $(y+6)(y-6)$. None of the other answer choices are valid factorizations.

Factor Completely y2−36y ^ { 2 } - 36y2−36 A) (y2+6)(y2−6)\left( y ^ { 2 } + 6 \right) \left( y ^ { 2 } - 6 \right)(y2+6)(y2−6)

Factor Completely $y ^ { 2 } - 36$ A) $\left( y ^ { 2 } + 6 \right) \left( y ^ { 2 } - 6 \right)$