Factor completely.
-$$9 m ^ { 2 } - \frac { 4 } { 9 }$$
A) $\left( 3 m + \frac { 2 } { 3 } \right) ^ { 2 }$
B) $\left( 3 m - \frac { 2 } { 3 } \right) ^ { 2 }$
C) $\left( 3 m + \frac { 2 } { 3 } \right) \left( 3 m - \frac { 2 } { 3 } \right)$
D) Prime

Question

Quizplus · Accepted Answer

We begin by noticing that $9m^2$ is a perfect square. We can rewrite the expression as follows:

$$9m^2-\frac{4}{9}=\left(3might)^2-\left(\frac{2}{3}ight)^2$$

We recognize that this is a difference of squares, which factors as follows:

$$\left(3m+\frac{2}{3}ight)\left(3m-\frac{2}{3}ight)$$

Therefore, the answer is $\boxed{	extbf{(C)}}.$

Factor Completely 9m2−499 m ^ { 2 } - \frac { 4 } { 9 }9m2−94​

Factor Completely $9 m ^ { 2 } - \frac { 4 } { 9 }$