Solve. Clear fractions first.
-$$\frac { 1 } { 3 } r + 2 = \frac { 1 } { 6 } r + \frac { 4 } { 3 }$$
A) 4
B) 3
C) $- 4$
D) $- 12$

Name: Solve. Clear fractions first. -\[\frac { 1 } { 3 } r + 2 = \frac { 1 } { 6 } r + \frac { 4 } { 3 }\] A) 4 B) 3 C) $- 4$ D) $- 12$
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The Answer of Solve. Clear fractions first.
-$$\frac { 1 } { 3 } r + 2 = \frac { 1 } { 6 } r + \frac { 4 } { 3 }$$
A) 4
B) 3
C) $- 4$
D) $- 12$

Solve Clear Fractions First 13r+2=16r+43\frac { 1 } { 3 } r + 2 = \frac { 1 } { 6 } r + \frac { 4 } { 3 }31​r+2=61​r+34​

Solve Clear Fractions First $\frac { 1 } { 3 } r + 2 = \frac { 1 } { 6 } r + \frac { 4 } { 3 }$