Solve.
-$$4 [ 3 - 3 ( x + 1 ) ] + 1 = 2 ( - 43 - x ) + 2 x + 43$$
A) $\frac { 11 } { 3 }$
B) 0
C) 11
D) $\frac { 11 } { 6 }$

Question

Quizplus · Accepted Answer

First, simplify both sides of the equation: Left side: $4[3 - 3(x + 1)] + 1 = 4[3 - 3x - 3] + 1 = 4(0 - 3x) + 1 = -12x + 1$. Right side: $2(-43 - x) + 2x + 43 = -86 - 2x + 2x + 43 = -43$. Setting both sides equal: $-12x + 1 = -43$, solving for x gives $x = \frac{11}{3}$.

Solve - 4[3−3(x+1)]+1=2(−43−x)+2x+434 [ 3 - 3 ( x + 1 ) ] + 1 = 2 ( - 43 - x ) + 2 x + 434[3−3(x+1)]+1=2(−43−x)+2x+43

Solve
- $4 [ 3 - 3 ( x + 1 ) ] + 1 = 2 ( - 43 - x ) + 2 x + 43$