Solve.
-$38 m ^ { 2 } + 48 m + 11 = 0$
A) $\frac { - 24 \pm \sqrt { 994 } } { 38 }$
B) $\frac { - 24 \pm \sqrt { 158 } } { 76 }$
C) $\frac { - 48 \pm \sqrt { 158 } } { 38 }$
D) $\frac { - 24 \pm \sqrt { 158 } } { 38 }$

Question

Quizplus · Accepted Answer

We can use the quadratic formula, which states that for an equation of the form $ax^2 + bx + c = 0$, the solutions are given by:

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

Comparing our equation to this form, we see that $a = 38$, $b = 48$, and $c = 11$. Substituting into the quadratic formula, we get:

$$m = \frac{-48 \pm \sqrt{48^2 - 4(38)(11)}}{2(38)} = \frac{-24 \pm \sqrt{158}}{38}$$

Therefore, the answer is D, $\frac{-24 \pm \sqrt{158}}{38}$.

Solve - 38m2+48m+11=038 m ^ { 2 } + 48 m + 11 = 038m2+48m+11=0

Solve
- $38 m ^ { 2 } + 48 m + 11 = 0$