Solve.
-$$x ^ { 2 } + x + 4 = 0$$

Name: Solve. -\[x ^ { 2 } + x + 4 = 0\]
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Question

Quizplus · Accepted Answer

We can use the quadratic formula:
$$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$
In this case, $a=1$, $b=1$, and $c=4$. Substituting these values, we get:
$$x = \frac{-1 \pm \sqrt{1-4(1)(4)}}{2(1)} = \frac{-1 \pm \sqrt{-15}}{2} = -\frac{1}{2} \pm \frac{\sqrt{15}}{2}i$$
Therefore, the answer is $\boxed{	ext{B}}$.

Solve - x2+x+4=0x ^ { 2 } + x + 4 = 0x2+x+4=0

Solve
- $x ^ { 2 } + x + 4 = 0$