The force between two charged particles can be calculated using the following equation: $$F = k \frac { q _ { 1 } q _ { 2 } } { r ^ { 2 } }$$
where
$$\begin{array} { l }
F = \text { force in newtons } \
G = \text { electrostatic constant } \
q _ { 1 } = \text { charge of particle } 1 \text { in coulombs } \
q _ { 2 } = \text { charge of particle } 2 \text { in coulombs } \
r = \text { distance between particles in meters }
\end{array}$$
What is the appropriate unit for $k$ if the preceding equation is to be homogeneous in units?

Question

The force between two charged particles can be calculated using the following equation: $$F = k \frac { q _ { 1 } q _ { 2 } } { r ^ { 2 } }$$
where
$$\begin{array} { l } 
F = \text { force in newtons } \
G = \text { electrostatic constant } \
q _ { 1 } = \text { charge of particle } 1 \text { in coulombs } \
q _ { 2 } = \text { charge of particle } 2 \text { in coulombs } \
r = \text { distance between particles in meters }
\end{array}$$
What is the appropriate unit for $k$ if the preceding equation is to be homogeneous in units?

Quizplus · Accepted Answer

The Answer of The force between two charged particles can be calculated using the following equation: $$F = k \frac { q _ { 1 } q _ { 2 } } { r ^ { 2 } }$$
where
$$\begin{array} { l } 
F = \text { force in newtons } \
G = \text { electrostatic constant } \
q _ { 1 } = \text { charge of particle } 1 \text { in coulombs } \
q _ { 2 } = \text { charge of particle } 2 \text { in coulombs } \
r = \text { distance between particles in meters }
\end{array}$$
What is the appropriate unit for $k$ if the preceding equation is to be homogeneous in units?

The Force Between Two Charged Particles Can Be Calculated Using F=kq1q2r2F = k \frac { q _ { 1 } q _ { 2 } } { r ^ { 2 } }F=kr2q1​q2​​

The Force Between Two Charged Particles Can Be Calculated Using $F = k \frac { q _ { 1 } q _ { 2 } } { r ^ { 2 } }$