Given that the forces $\mathbf { F } _ { 1 } = ( - 10,3 )$ , $\mathbf { F } _ { 2 } = ( - 4,1 )$
And $\mathbf { F } _ { 3 } = \langle 4 , - 10 \rangle$
Are acting on a point $p$
, find the resultant force
A) $( - 6,14 )$
B) $( - 10 , - 6 )$
C) $( - 1 , - 6 )$
D) $( - 18,6 )$
E) $( 18 , - 6 )$

Question

Quizplus · Accepted Answer

The resultant force is found by adding the vectors: $(-10, 3) + (-4, 1) + (4, -10) = (-10 - 4 + 4, 3 + 1 - 10) = (-10, -6)$.

Given That the Forces F1=(−10,3)\mathbf { F } _ { 1 } = ( - 10,3 )F1​=(−10,3)

Given That the Forces $\mathbf { F } _ { 1 } = ( - 10,3 )$