$\mathbf { u } = \left( - \frac { 1 } { 2 } , 2 \right\rangle$ is orthogonal to $\mathbf { v } = \left( - 2 , \frac { 1 } { 2 } \right)$

Name: $\mathbf { u } = \left( - \frac { 1 } { 2 } , 2 \right\rangle$ is orthogonal to $\mathbf { v } = \left( - 2 , \frac { 1 } { 2 } \right)$
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Question

Quizplus · Accepted Answer

Two vectors are orthogonal if their dot product is zero. The dot product of $\mathbf{u}$ and $\mathbf{v}$ is $(- \frac{1}{2})(-2) + (2)(\frac{1}{2}) = 1 + 1 = 2$, which is not zero.

u=(−12,2⟩\mathbf { u } = \left( - \frac { 1 } { 2 } , 2 \right\rangleu=(−21​,2⟩

$\mathbf { u } = \left( - \frac { 1 } { 2 } , 2 \right\rangle$