Find all real solutions of the equation. $\frac { 1 } { x - 4 } - \frac { 25 } { x ^ { 2 } } = 0$
A) x = 0, x = 20
B) x = 5, x = 20
C) x = 0, x = -25
D) x = 20, x = 80
E) none of these

Question

Quizplus · Accepted Answer

To solve the equation $\frac { 1 } { x - 4 } - \frac { 25 } { x ^ { 2 } } = 0$, we first find a common denominator, which is $x^2(x-4)$. This gives us $\frac{x^2 - 25(x-4)}{x^2(x-4)} = 0$, simplifying to $x^2 - 25x + 100 = 0$. Factoring or using the quadratic formula, we find $x = 5$ and $x = 20$ as the solutions.

Find All Real Solutions of the Equation 1x−4−25x2=0\frac { 1 } { x - 4 } - \frac { 25 } { x ^ { 2 } } = 0x−41​−x225​=0

Find All Real Solutions of the Equation $\frac { 1 } { x - 4 } - \frac { 25 } { x ^ { 2 } } = 0$