Which of the following conditions will correctly check if the String variable early comes before "middle" alphabetically? A)if (greeting 0) C)if (greeting.compareTo("middle") == 0) D)if (early.compareTo("middle")

Question

Which of the following conditions will correctly check if the String variable early comes before "middle" alphabetically?
A)if (greeting <= "middle")
B)if (greeting.compareTo("middle") > 0)
C)if (greeting.compareTo("middle") == 0)
D)if (early.compareTo("middle") < 0)

Quizplus · Accepted Answer

Comparing two strings lexicographically means checking which string comes first in the dictionary. The compareTo() method of the String class can be used for this purpose. It returns an integer value that indicates the relationship between two strings. If the value returned is less than 0, the first string is lexicographically smaller than the second string. Therefore, option D is correct for checking if the String variable early comes before "middle" alphabetically.

Which of the Following Conditions Will Correctly Check If the String