On January 23, 1916, the temperature outside the city hall in Browning, Montana, was approximately $6.72 ^ { \circ } \mathrm { C }$ On January 24, 1916, the temperature was approximately $- 48.32 ^ { \circ } \mathrm { C }$ Find the difference between the temperatures in Browning on these two days.

Question

Quizplus · Accepted Answer

To find the difference in temperatures, subtract the first day's temperature from the second day's temperature: $-48.32 - 6.72 = -55.04$. The difference is $55.04 ^{\circ}C$, considering the absolute value of the change.

On January 23, 1916, the Temperature Outside the City Hall 6.72∘C6.72 ^ { \circ } \mathrm { C }6.72∘C

On January 23, 1916, the Temperature Outside the City Hall $6.72 ^ { \circ } \mathrm { C }$