A new baby measured $10 \frac { 1 } { 16 }$ inches at birth. The baby grew $\frac { 15 } { 16 }$ inch in August and $\frac { 5 } { 16 }$ inch in September. How long is the baby at its two-month checkup?

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The baby's original length was $10 \frac { 1 } { 16 }$ inches. After growing $\frac { 15 } { 16 }$ inch in August and $\frac { 5 } { 16 }$ inch in September, the total growth is $\frac { 15 } { 16 } + \frac { 5 } { 16 } = \frac { 20 } { 16 } = 1 \frac { 4 } { 16 }$ inches. Adding this to the original length gives $10 \frac { 1 } { 16 } + 1 \frac { 4 } { 16 } = 11 \frac { 5 } { 16 }$ inches.

A New Baby Measured 1011610 \frac { 1 } { 16 }10161​

A New Baby Measured $10 \frac { 1 } { 16 }$