Solve the equation below. $( x + 4 ) ^ { 2 } + ( x + 2 ) = ( x + 4 ) ( x + 2 )$
A) $x = 1 \frac { 1 } { 3 }$
B) $x = - 3 \frac { 1 } { 3 }$
C) $x = - 2 \frac { 2 } { 3 }$
D) $x = - \frac { 1 } { 3 }$
E) $x = 4 \frac { 2 } { 3 }$

Question

Quizplus · Accepted Answer

Expanding both sides of the equation gives $x^2 + 8x + 16 + x + 2 = x^2 + 6x + 8$. Simplifying, we get $9x + 18 = 6x + 8$, leading to $3x = -10$, so $x = -\frac{10}{3}$ or $x = -3\frac{1}{3}$.

Solve the Equation Below (x+4)2+(x+2)=(x+4)(x+2)( x + 4 ) ^ { 2 } + ( x + 2 ) = ( x + 4 ) ( x + 2 )(x+4)2+(x+2)=(x+4)(x+2)

Solve the Equation Below $( x + 4 ) ^ { 2 } + ( x + 2 ) = ( x + 4 ) ( x + 2 )$