Find the real solutions of the polynomial equation below. $x ^ { 6 } - 729 = 0$
A) $x = \pm 6$
B) $x = \pm 2$
C) $x = \pm 3$
D) $x = \pm 4$
E) $x = \pm 1$

Name: Find the real solutions of the polynomial equation below. $x ^ { 6 } - 729 = 0$ A) $x = \pm 6$ B) $x = \pm 2$ C) $x = \pm 3$ D) $x = \pm 4$ E) $x = \pm 1$
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Question

Quizplus · Accepted Answer

The equation $x^6 - 729 = 0$ can be rewritten as $x^6 = 729$. Taking the sixth root of both sides gives $x = \pm \sqrt[6]{729}$. Since $729 = 3^6$, the solutions are $x = \pm 3$.

Find the Real Solutions of the Polynomial Equation Below x6−729=0x ^ { 6 } - 729 = 0x6−729=0

Find the Real Solutions of the Polynomial Equation Below $x ^ { 6 } - 729 = 0$