The upper limit of the 90% confidence interval for µ, given that n = 64, $$\bar { X }$$ = 70 and $\sigma$ = 20, is 65.89.

Question

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The upper limit of a confidence interval is calculated using the formula: $\bar{X} + Z \frac{\sigma}{\sqrt{n}}$, where $\bar{X}$ is the sample mean, $Z$ is the Z-score corresponding to the desired confidence level, $\sigma$ is the population standard deviation, and $n$ is the sample size. Given $n = 64$, $\bar{X} = 70$, and $\sigma = 20$, for a 90% confidence level (where Z is approximately 1.645), the upper limit would be higher than 65.89.

The Upper Limit of the 90% Confidence Interval for µ Xˉ\bar { X }Xˉ

The Upper Limit of the 90% Confidence Interval for µ $\bar { X }$