Given that Z is a standard normal variable, the value z for which P(Z $\le$ z) = 0.2580 is:
A)0.70.
B)0.758.
C)-0.65.
D)0.242.

Name: Given that Z is a standard normal variable, the value z for which P(Z $\le$ z) = 0.2580 is: A)0.70. B)0.758. C)-0.65. D)0.242.
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Question

Quizplus · Accepted Answer

Using a standardized normal distribution table, we look for the closest probability to 0.2580, which is 0.2582. The corresponding z-value for this probability is -0.65. Therefore, the answer is C.

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