Let X represent the number of computers in Australian households who own computers. The probability distribution of X is as follows: $$\begin{array} { | l | r | r | r | r | r | }
\hline x & 1 & 2 & 3 & 4 & 5 \
\hline p ( x ) & 0.25 & 0.33 & 0.17 & 0.15 & 0.10 \
\hline
\end{array}$$ What is the probability that a randomly selected Australian household will have:
a. more than 2 computers?
b. between 2 and 5 computers, inclusive?
c. fewer than 3 computers?

Question

Let X represent the number of computers in Australian households who own computers. The probability distribution of X is as follows: $$\begin{array} { | l | r | r | r | r | r | } 
\hline x & 1 & 2 & 3 & 4 & 5 \
\hline p ( x ) & 0.25 & 0.33 & 0.17 & 0.15 & 0.10 \
\hline
\end{array}$$ What is the probability that a randomly selected Australian household will have:
a. more than 2 computers?
b. between 2 and 5 computers, inclusive?
c. fewer than 3 computers?

Quizplus · Accepted Answer

The Answer of Let X represent the number of computers in Australian households who own computers. The probability distribution of X is as follows: $$\begin{array} { | l | r | r | r | r | r | } 
\hline x & 1 & 2 & 3 & 4 & 5 \
\hline p ( x ) & 0.25 & 0.33 & 0.17 & 0.15 & 0.10 \
\hline
\end{array}$$ What is the probability that a randomly selected Australian household will have:
a. more than 2 computers?
b. between 2 and 5 computers, inclusive?
c. fewer than 3 computers?

Let X Represent the Number of Computers in Australian Households x12345p(x)0.250.330.170.150.10\begin{array} { | l | r | r | r | r | r | } \hline x & 1 & 2 & 3 & 4 & 5 \\\hline p ( x ) & 0.25 & 0.33 & 0.17 & 0.15 & 0.10 \\\hline\end{array}xp(x)​10.25​20.33​30.17​40.15​50.10​​

Let X Represent the Number of Computers in Australian Households $\begin{array} { | l | r | r | r | r | r | } \hline x & 1 & 2 & 3 & 4 & 5 \\\hline p ( x ) & 0.25 & 0.33 & 0.17 & 0.15 & 0.10 \\\hline\end{array}$