If P(A) = 0.60, P(B) = 0.58, and P(A $\cup$ B) = 0.70, then P(A $\cap$ B) is:
A)0.60.
B)0.70.
C)0.48.
D)0.58.

Question

Quizplus · Accepted Answer

We can use the formula P(AUB) = P(A) + P(B) - P(A∩B) to solve the problem.
Given:
P(A) = 0.60
P(B) = 0.58
P(A∪B) = 0.70 (where ∪ represents the union of events)
We need to find P(A∩B), where ∩ represents the intersection of events.
Using the formula, we get:
0.70 = 0.60 + 0.58 - P(A∩B)
P(A∩B) = 0.48
Therefore, the answer is C) 0.48.

If P(A) = 0 ∪\cup∪ B) = 070, Then P(A ∩\cap∩ B) Is: A)0

If P(A) = 0 $\cup$ B) = 070, Then P(A $\cap$ B) Is:
A)0