voltage across a capacitor with capacitance of 39 is given by $\mu \mathrm { F }$ $$v ( t ) = \left\{ \begin{array} { c }
- 30 t , \quad 0 \leq t

Question

voltage across a capacitor with capacitance of 39 is given by $\mu \mathrm { F }$ $$v ( t ) = \left\{ \begin{array} { c } 
- 30 t , \quad 0 \leq t < 5 \
90 t - 600 , \quad 5 \leq t < 10 \
- 60 t + 900 , \quad 10 \leq t < 15 \
0 , \quad \text { otherwise }
\end{array} \right.$$ Find the current through the capacitor i(t) and plot the voltage and current as a function of time.

Quizplus · Accepted Answer

The Answer of voltage across a capacitor with capacitance of 39 is given by $\mu \mathrm { F }$ $$v ( t ) = \left\{ \begin{array} { c } 
- 30 t , \quad 0 \leq t < 5 \
90 t - 600 , \quad 5 \leq t < 10 \
- 60 t + 900 , \quad 10 \leq t < 15 \
0 , \quad \text { otherwise }
\end{array} \right.$$ Find the current through the capacitor i(t) and plot the voltage and current as a function of time.

Voltage Across a Capacitor with Capacitance of 39 Is Given μF\mu \mathrm { F }μF

Voltage Across a Capacitor with Capacitance of 39 Is Given $\mu \mathrm { F }$