In the circuit shown below, let $\mathrm { V } _ { \mathrm { s } } = 3 \mathrm {~V} , \mathrm { I } _ { \mathrm { s } } = 1 \mathrm {~mA} , \mathrm { R } _ { 1 } = 3 \mathrm { k } \Omega , \mathrm { R } _ { 2 } = 2.5 \mathrm { k } \Omega , \mathrm { R } _ { 3 } = 1 \mathrm { k } \Omega$
Use mesh analysis to find mesh currents $I _ { 1 }$ and $I _ { 2 }$. Also, find $V _ { 1 }$.

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The Answer of In the circuit shown below, let $\mathrm { V } _ { \mathrm { s } } = 3 \mathrm {~V} , \mathrm { I } _ { \mathrm { s } } = 1 \mathrm {~mA} , \mathrm { R } _ { 1 } = 3 \mathrm { k } \Omega , \mathrm { R } _ { 2 } = 2.5 \mathrm { k } \Omega , \mathrm { R } _ { 3 } = 1 \mathrm { k } \Omega$
Use mesh analysis to find mesh currents $I _ { 1 }$ and $I _ { 2 }$. Also, find $V _ { 1 }$.

In the Circuit Shown Below, Let Use Mesh Analysis to Find Mesh Currents