Solve.
-The gasoline/oil ratio for a certain lawn mower is 20 to 1. If 1 gallon equals 128 fluid ounces, how many fluid ounces of oil should be mixed with 4 gallons of gasoline? Round the answer to the nearest whole ounce.

Question

Quizplus · Accepted Answer

To find the ratio of gasoline to oil we convert 20 to 1 to the fraction 20/1 or 20 parts gasoline to 1 part oil. 
This means for every 21 parts of the mixture, 20 parts are gasoline and 1 part is oil. 
So, for 4 gallons of gasoline we need to add 1/20th of that amount of oil. 
(1/20) x 4 gallons = 0.2 gallons of oil 
Now we need to convert gallons to fluid ounces. 
0.2 gallons x 128 fluid ounces/gallon = 25.6 fluid ounces 
Rounding to the nearest whole ounce gives us an answer of 26 fluid ounces. To determine how much oil should be mixed with 4 gallons of gasoline, we need to set up a proportion using the gasoline/oil ratio.

20 to 1 means that for every 20 parts of gasoline, we need 1 part of oil. So, we can set up the proportion:

20/1 = 4(x)/128

Simplifying, we get:

x = 26

So, we need 26 fluid ounces of oil to mix with 4 gallons of gasoline. Rounded to the nearest whole ounce, the answer is 26 fluid ounces. Therefore, the best choice is B.

Solve. -The Gasoline/oil Ratio for a Certain Lawn Mower Is 20