Solve.
-$\left| \frac { 1 } { 4 } x - 2 \right| = \left| \frac { 1 } { 2 } x + 2 \right|$
A) $\varnothing$
B)0, - 1
C){0, -16}
D) $\left\{ 0 , - \frac { 16 } { 3 } \right\}$

Question

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The Answer of Solve.
-$\left| \frac { 1 } { 4 } x - 2 \right| = \left| \frac { 1 } { 2 } x + 2 \right|$
A) $\varnothing$
B)0, - 1
C){0, -16}
D) $\left\{ 0 , - \frac { 16 } { 3 } \right\}$

Solve - ∣14x−2∣=∣12x+2∣\left| \frac { 1 } { 4 } x - 2 \right| = \left| \frac { 1 } { 2 } x + 2 \right|​41​x−2​=​21​x+2​

Solve
- $\left| \frac { 1 } { 4 } x - 2 \right| = \left| \frac { 1 } { 2 } x + 2 \right|$