Solve the equation.
-$20 y ^ { 2 } + 31 y + 12 = 0$

Name: Solve the equation. -$20 y ^ { 2 } + 31 y + 12 = 0$
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Question

Quizplus · Accepted Answer

This quadratic equation can be solved by factoring or using the quadratic formula. The correct roots are $- \frac { 4 } { 5 }$ and $- \frac { 3 } { 4 }$, which can be found by factoring the equation into $(5y + 4)(4y + 3) = 0$, leading to the solutions $y = - \frac { 4 } { 5 }$ and $y = - \frac { 3 } { 4 }$.

Solve the Equation 20y2+31y+12=020 y ^ { 2 } + 31 y + 12 = 020y2+31y+12=0

Solve the Equation $20 y ^ { 2 } + 31 y + 12 = 0$