Solve the problem.
-Jamil always throws loose change into a pencil holder on his desk and takes it out every two weeks. This time it is all nickels and dimes. There are 3 times as many dimes as nickels, and the value of the dimes is $1.75 more
Than the value of the nickels. How many nickels and dimes does Jamil have?
A)7 nickels and 21 dimes
B)6 nickels and 18 dimes
C)21 nickels and 7 dimes
D)8 nickels and 24 dimes

Question

Quizplus · Accepted Answer

Let the number of nickels be $n$ and the number of dimes be $d$. Given that $d = 3n$ and the value difference is $1.75, which translates to 175 cents. The value of dimes is $10d$ cents and the value of nickels is $5n$ cents. The equation based on the value difference is $10d - 5n = 175$. Substituting $d = 3n$ into the equation gives $30n - 5n = 175$, which simplifies to $25n = 175$. Solving for $n$ gives $n = 7$, and thus $d = 3n = 21$. Therefore, Jamil has 7 nickels and 21 dimes.

Solve the Problem. -Jamil Always Throws Loose Change into a Pencil Holder on Pencil