Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l }
x + y = 33 \
x - y = 13
\end{array} \right.$
A)No solution
B)(10, 23)
C) $\left( \frac { 33 } { 2 } , \frac { 13 } { 2 } \right)$
D)(23, 10)

Question

Solve the system of equations by the addition method.
-$\left\{ \begin{array} { l } 
x + y = 33 \
x - y = 13
\end{array} \right.$
A)No solution
B)(10, 23)
C) $\left( \frac { 33 } { 2 } , \frac { 13 } { 2 } \right)$
D)(23, 10)

Quizplus · Accepted Answer

Adding the equations gives $2x = 46$, so $x = 23$. Substituting $x = 23$ into the first equation gives $23 + y = 33$, so $y = 10$. Thus, the solution is (23, 10).

Solve the System of Equations by the Addition Method {x+y=33x−y=13\left\{ \begin{array} { l } x + y = 33 \\x - y = 13\end{array} \right.{x+y=33x−y=13​

Solve the System of Equations by the Addition Method $\left\{ \begin{array} { l } x + y = 33 \\x - y = 13\end{array} \right.$