Find the margin of error for the given values of c, $\sigma$ and n. $\mathrm { c } = 0.95 , \sigma = 677 , \mathrm { n } = 40$
A)$210
B)$77
C)$2891
D)$7

Question

Quizplus · Accepted Answer

The margin of error (E) for a given confidence level (c), standard deviation ($\sigma$), and sample size (n) can be calculated using the formula: $E = Z \times \frac{\sigma}{\sqrt{n}}$, where Z is the Z-score corresponding to the confidence level. For a 0.95 confidence level, the Z-score is approximately 1.96. Plugging in the given values: $E = 1.96 \times \frac{677}{\sqrt{40}} \approx 210$.

Find the Margin of Error for the Given Values of C