A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence interval for the proportion of homeless persons who are veterans.

Question

Quizplus · Accepted Answer

The proportion of homeless persons who are veterans is calculated as $p = \frac{63}{280}$. To construct a 90% confidence interval for the proportion, we use the formula: $$p \pm z \sqrt{\frac{p(1-p)}{n}}$$, where $p$ is the sample proportion, $n$ is the sample size, and $z$ is the z-score corresponding to the confidence level. For a 90% confidence level, the z-score is approximately 1.645. Plugging in the values, we get the confidence interval as approximately (0.184, 0.266).

A Survey of 280 Homeless Persons Showed That 63 Were