IQ test scores are normally distributed with a mean of 105 and a standard deviation of 11. An individualʹs IQ score is found to be 119. Find the z-score corresponding to this value.
A)1.27
B)-1.27
C)0.79
D)-0.79

Question

Quizplus · Accepted Answer

The z-score is calculated using the formula $z = \frac{(X - \mu)}{\sigma}$, where $X$ is the value in question, $\mu$ is the mean, and $\sigma$ is the standard deviation. Plugging in the given values, $z = \frac{(119 - 105)}{11} = \frac{14}{11} = 1.27$.

IQ Test Scores Are Normally Distributed with a Mean of 105