An airline reports that it has been experiencing a 15% rate of no-shows on advanced reservations. Among 150 advanced reservations, find the probability that there will be fewer than 20 no-shows.
A)0.2451
B)0.7549
C)0.7967
D)0.3187

Question

Quizplus · Accepted Answer

The probability of fewer than 20 no-shows is the sum of the probabilities of 0, 1, 2, ..., 19 no-shows. Using the binomial distribution, we can calculate these probabilities as follows:P(0 no-shows) = (0.85)^150 * (0.15)^0 = 0.0000P(1 no-show) = (0.85)^149 * (0.15)^1 = 0.0001P(2 no-shows) = (0.85)^148 * (0.15)^2 = 0.0006...P(19 no-shows) = (0.85)^131 * (0.15)^19 = 0.0245Therefore, the probability of fewer than 20 no-shows is:P(0 no-shows) + P(1 no-show) + ... + P(19 no-shows) = 0.2451

An Airline Reports That It Has Been Experiencing a 15