Determine the probability distribution?s missing value. The probability that a tutor sees 0, 1, 2, 3, or 4 students on a given day. $$\begin{array} { l | c | c | c | c | c }
\mathrm { x } & 0 & 1 & 2 & 3 & 4 \
\hline \mathrm { P } ( \mathrm { x } ) & ? & 0.15 & 0.20 & 0.20 & 0.25
\end{array}$$
A)0.20
B)0.50
C)0.80
D)1.0

Question

Determine the probability distribution?s missing value. The probability that a tutor sees 0, 1, 2, 3, or 4 students on a given day. $$\begin{array} { l | c | c | c | c | c } 
\mathrm { x } & 0 & 1 & 2 & 3 & 4 \
\hline \mathrm { P } ( \mathrm { x } ) & ? & 0.15 & 0.20 & 0.20 & 0.25
\end{array}$$
A)0.20
B)0.50
C)0.80
D)1.0

Quizplus · Accepted Answer

The sum of the probabilities in a probability distribution must equal 1. Adding the given probabilities: 0.15 + 0.20 + 0.20 + 0.25 = 0.80. Therefore, the missing value must be 1 - 0.80 = 0.20 to make the total probability equal to 1.

Determine the Probability Distribution?s Missing Value A)020 B)0

Determine the Probability Distribution?s Missing Value A)020
B)0