Use the fundamental counting principle to solve the problem.
-How many different codes of 4 digits are possible if the first digit must be 3, 4, or 5 and if the code may not end in 0?
A)2700
B)300
C)2999
D)3000

Question

Quizplus · Accepted Answer

For the first digit, there are 3 choices (3, 4, or 5). For each of the next two digits, there are 10 choices (0 through 9). For the last digit, there are 9 choices (1 through 9, since it cannot be 0). Thus, the total number of codes is 3 * 10 * 10 * 9 = 2700.

Use the Fundamental Counting Principle to Solve the Problem